a=(2b-6)/(a+1)

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Solution for a=(2b-6)/(a+1) equation: 


D( x )

a+1 = 0

a+1 = 0

a+1 = 0

a+1 = 0

x naleu017Cy do R

x belongs to the empty set

a = (2*b-6)/(a+1)

x belongs to the empty set

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