a=(3a*a)*3+2*a*a

Solution for a=(3a*a)*3+2*a*a equation:

a=(3a*a)*3+2a*a

We move all terms to the left:

a-((3a*a)*3+2a*a)=0

We add all the numbers together, and all the variables

a-((+3a*a)*3+2a*a)=0


We calculate terms in parentheses: -((+3a*a)*3+2a*a), so:

(+3a*a)*3+2a*a

We multiply parentheses

9a^2+2a*a

Wy multiply elements

9a^2+2a^2

We add all the numbers together, and all the variables

11a^2

Back to the equation:

-(11a^2)


determiningTheFunctionDomain
-11a^2+a=0

a = -11; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-11)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-11}=\frac{-2}{-22}
=1/11
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-11}=\frac{0}{-22}
=0
$