a=(b+c)/2

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Solution for a=(b+c)/2 equation: 


x in (-oo:+oo)

a = (b+c)/2 // - (b+c)/2

a-((b+c)/2) = 0

(-1*(b+c))/2+a = 0

(-1*(b+c))/2+(2*a)/2 = 0

2*a-1*(b+c) = 0

2*a-b-c = 0

(2*a-b-c)/2 = 0

(2*a-b-c)/2 = 0 // * 2

2*a-b-c = 0

x belongs to the empty set

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