a=(b-c)/c

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Solution for a=(b-c)/c equation: 


x in (-oo:+oo)

a = (b-c)/c // - (b-c)/c

a-((b-c)/c) = 0

(-1*(b-c))/c+a = 0

(-1*(b-c))/c+(a*c)/c = 0

a*c-1*(b-c) = 0

c-b+a*c = 0

(c-b+a*c)/c = 0

(c-b+a*c)/c = 0 // * c

c-b+a*c = 0

x belongs to the empty set

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