a=(f-g/2)h

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Solution for a=(f-g/2)h equation: 


x in (-oo:+oo)

a = h*(f-(g/2)) // - h*(f-(g/2))

a-(h*(f-(g/2))) = 0

a-1*h*(f-1/2*g) = 0

a-1*h*(f-1/2*g) = 0

a-(f*h)+1/2*g*h = 0

a-(f*h)+1/2*g*h = 0

x belongs to the empty set

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