a=1/(1+x)

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Solution for a=1/(1+x) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

a = 1/(x+1) // - 1/(x+1)

a-(1/(x+1)) = 0

a-(x+1)^-1 = 0

a-1/(x+1) = 0

(a*(x+1))/(x+1)-1/(x+1) = 0

a*(x+1)-1 = 0

a*x+a-1 = 0

(a*x+a-1)/(x+1) = 0

(a*x+a-1)/(x+1) = 0 // * x+1

a*x+a-1 = 0

a*x+a-1 = 0 // - a-1

a*x = -(a-1) // : a

x = (-(a-1))/a

x = (1-a)/a

x = (1-a)/a

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