a=1/5(b+c-d)

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Solution for a=1/5(b+c-d) equation: 


x in (-oo:+oo)

a = (1/5)*(b+c-d) // - (1/5)*(b+c-d)

a-((1/5)*(b+c-d)) = 0

(-1/5)*(b+c-d)+a = 0

a-1/5*(b+c-d) = 0

a-1/5*(b+c-d) = 0

a-1/5*b-1/5*c+1/5*d = 0

a-1/5*b-1/5*c+1/5*d = 0

x belongs to the empty set

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