a=1h/2(b1+b2)

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Solution for a=1h/2(b1+b2) equation: 


x in (-oo:+oo)

a = ((1*h)/2)*(b^2+b^1) // - ((1*h)/2)*(b^2+b^1)

a-(((1*h)/2)*(b^2+b^1)) = 0

a-((h/2)*(b^2+b)) = 0

a-1*1/2*h*(b^2+b) = 0

a-1*1/2*h*(b^2+b) = 0

a-1/2*b^2*h-1/2*b*h = 0

a-1/2*b^2*h-1/2*b*h = 0

x belongs to the empty set

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