a=2(3-2a)-3(1-a)

Solution for a=2(3-2a)-3(1-a) equation:

a=2(3-2a)-3(1-a)

We move all terms to the left:

a-(2(3-2a)-3(1-a))=0

We add all the numbers together, and all the variables

a-(2(-2a+3)-3(-1a+1))=0


We calculate terms in parentheses: -(2(-2a+3)-3(-1a+1)), so:

2(-2a+3)-3(-1a+1)

We multiply parentheses

-4a+3a+6-3

We add all the numbers together, and all the variables

-1a+3

Back to the equation:

-(-1a+3)


We get rid of parentheses

a+1a-3=0

We add all the numbers together, and all the variables

2a-3=0

We move all terms containing a to the left, all other terms to the right

2a=3

a=3/2

a=1+1/2