a=3(a-3)+15+2a+9

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Solution for a=3(a-3)+15+2a+9 equation: 



a=3(a-3)+15+2a+9

We move all terms to the left:

a-(3(a-3)+15+2a+9)=0



We calculate terms in parentheses: -(3(a-3)+15+2a+9), so:

3(a-3)+15+2a+9

determiningTheFunctionDomain
3(a-3)+2a+15+9

We add all the numbers together, and all the variables

2a+3(a-3)+24

We multiply parentheses

2a+3a-9+24

We add all the numbers together, and all the variables

5a+15

Back to the equation:

-(5a+15)



We get rid of parentheses

a-5a-15=0

We add all the numbers together, and all the variables

-4a-15=0

We move all terms containing a to the left, all other terms to the right

-4a=15

a=15/-4

a=-3+3/4

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