a=33a2+5a

Solution for a=33a2+5a equation:

a=33a^2+5a

We move all terms to the left:

a-(33a^2+5a)=0

We get rid of parentheses

-33a^2+a-5a=0

We add all the numbers together, and all the variables

-33a^2-4a=0

a = -33; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-33)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-33}=\frac{0}{-66}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-33}=\frac{8}{-66}
=-4/33
$