a=3b-4;a+b=16

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2x+y=8
x+3y=14

Solution for a=3b-4;a+b=16 system of equations: 


  • /| a-(3*b)+4 = 0| a+b-16 = 0
  • We try to solve the equation: a-(3*b)+4 = 0
  • a-3*b+4 = 0 // - a+4
  • -3*b = -(a+4) // : -3
  • b = (-(a+4))/(-3)
  • b = (a+4)/3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| (a+4)/3+a-16 = 0| b = (a+4)/3
  • (a+4)/3+a-16 = 0
  • 4/3*a-16+4/3 = 0
  • 4/3*a-44/3 = 0
  • 4/3*a-44/3 = 0 // + 44/3
  • 4/3*a = 44/3 // : 4/3
  • a = 44/3/4/3
  • a = 11
  • We insert the solution into one of the initial equations of our system of equations
  • For b = (a+4)/3: 
  • b = (4+11)/3
  • b = 15/3
  • b = 5
  • We get a system of equations:
  • /| b = 5| a = 11

 

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