a=5/9a+7

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Solution for a=5/9a+7 equation:



a=5/9a+7
We move all terms to the left:
a-(5/9a+7)=0
Domain of the equation: 9a+7)!=0
a∈R
We get rid of parentheses
a-5/9a-7=0
We multiply all the terms by the denominator
a*9a-7*9a-5=0
Wy multiply elements
9a^2-63a-5=0
a = 9; b = -63; c = -5;
Δ = b2-4ac
Δ = -632-4·9·(-5)
Δ = 4149
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4149}=\sqrt{9*461}=\sqrt{9}*\sqrt{461}=3\sqrt{461}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-3\sqrt{461}}{2*9}=\frac{63-3\sqrt{461}}{18} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+3\sqrt{461}}{2*9}=\frac{63+3\sqrt{461}}{18} $

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