a=6(11-4)/5(2)+4+10

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Solution for a=6(11-4)/5(2)+4+10 equation:



a=6(11-4)/5(2)+4+10
We move all terms to the left:
a-(6(11-4)/5(2)+4+10)=0
We add all the numbers together, and all the variables
a-(67/52+4+10)=0
We get rid of parentheses
a-4-10-67/52=0
We multiply all the terms by the denominator
a*52-67-4*52-10*52=0
We add all the numbers together, and all the variables
a*52-795=0
Wy multiply elements
52a-795=0
We move all terms containing a to the left, all other terms to the right
52a=795
a=795/52
a=15+15/52

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