ab+(b+1)x=(a+x)b+c

Solution for ab+(b+1)x=(a+x)b+c equation:

Simplifying
ab + (b + 1) * x = (a + x) * b + c

Reorder the terms:
ab + (1 + b) * x = (a + x) * b + c

Reorder the terms for easier multiplication:
ab + x(1 + b) = (a + x) * b + c
ab + (1 * x + b * x) = (a + x) * b + c

Reorder the terms:
ab + (bx + 1x) = (a + x) * b + c
ab + (bx + 1x) = (a + x) * b + c

Reorder the terms for easier multiplication:
ab + bx + 1x = b(a + x) + c
ab + bx + 1x = (a * b + x * b) + c
ab + bx + 1x = (ab + bx) + c

Add '-1ab' to each side of the equation.
ab + bx + -1ab + 1x = ab + bx + -1ab + c

Reorder the terms:
ab + -1ab + bx + 1x = ab + bx + -1ab + c

Combine like terms: ab + -1ab = 0
0 + bx + 1x = ab + bx + -1ab + c
bx + 1x = ab + bx + -1ab + c

Reorder the terms:
bx + 1x = ab + -1ab + bx + c

Combine like terms: ab + -1ab = 0
bx + 1x = 0 + bx + c
bx + 1x = bx + c

Add '-1bx' to each side of the equation.
bx + -1bx + 1x = bx + -1bx + c

Combine like terms: bx + -1bx = 0
0 + 1x = bx + -1bx + c
1x = bx + -1bx + c

Combine like terms: bx + -1bx = 0
1x = 0 + c
1x = c

Solving
1x = c

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '1'.
x = c

Simplifying
x = c