abs((17x-4)/x)=16

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Solution for abs((17x-4)/x)=16 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

abs((17*x-4)/x) = 16 // - 16

abs((17*x-4)/x)-16 = 0

abs((17*x-4)/x)-16 = 0

x in (-oo:+oo)

abs((17*x-4)/x)

(17*x-4)/x >= 0

( 17*x-4 )

17*x-4 >= 0 // + 4

17*x >= 4 // : 17

x >= 4/17

( x )

x+0 >= 0 // - 0

x >= 0

(-oo:0)(0:4/17)(4/17:+oo)17*x-4--+x-++

x in (-oo:0> U <4/17:+oo)

(17*x-4)/x-16 = 0

x in (0:4/17)

-((17*x-4)/x)-16 = 0

abs((17*x-4)/x)-16 = 0

/| (17*x-4)/x-16 = 0 i x in (-oo:0> U <4/17:+oo)| -((17*x-4)/x)-16 = 0 i x in (0:4/17)

x in (-oo:0> U <4/17:+oo)

(17*x-4)/x-16 = 0

(17*x-4)/x+(-16*x)/x = 0

17*x-16*x-4 = 0

x-4 = 0

(x-4)/x = 0

(x-4)/x = 0 // * x

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (0:4/17)

-((17*x-4)/x)-16 = 0

(-1*(17*x-4))/x-16 = 0

(-1*(17*x-4))/x+(-16*x)/x = 0

-1*(17*x-4)-16*x = 0

4-33*x = 0

(4-33*x)/x = 0

(4-33*x)/x = 0 // * x

4-33*x = 0

4-33*x = 0 // - 4

-33*x = -4 // : -33

x = -4/(-33)

x = 4/33

x in { 4, 4/33 }

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