abs((3x-7)/19)-14=0

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Solution for abs((3x-7)/19)-14=0 equation:


x in (-oo:+oo)

abs((3*x-7)/19)-14 = 0

abs((3*x-7)/19)-14 = 0

x in (-oo:+oo)

abs((3*x-7)/19)

(3*x-7)/19 >= 0

( 19 )

19 >= 0

x naleu017Cy do R

( 3*x-7 )

3*x-7 >= 0 // + 7

3*x >= 7 // : 3

x >= 7/3

(-oo:7/3)(7/3:+oo)19++3*x-7-+

x in <7/3:+oo)

(3*x-7)/19-14 = 0

x in (-oo:7/3)

-((3*x-7)/19)-14 = 0

abs((3*x-7)/19)-14 = 0

/| -((3*x-7)/19)-14 = 0 i x in (-oo:7/3)| (3*x-7)/19-14 = 0 i x in <7/3:+oo)

x in (-oo:7/3)

-((3*x-7)/19)-14 = 0

(-1*(3*x-7))/19-14 = 0

(-1*(3*x-7))/19+(-14*19)/19 = 0

-1*(3*x-7)-14*19 = 0

-3*x-259 = 0

(-3*x-259)/19 = 0

(-3*x-259)/19 = 0 // * 19

-3*x-259 = 0

-3*x-259 = 0 // + 259

-3*x = 259 // : -3

x = 259/(-3)

x = -259/3

x in <7/3:+oo)

(3*x-7)/19-14 = 0

(3*x-7)/19+(-14*19)/19 = 0

3*x-14*19-7 = 0

3*x-273 = 0

(3*x-273)/19 = 0

(3*x-273)/19 = 0 // * 19

3*x-273 = 0

3*x-273 = 0 // + 273

3*x = 273 // : 3

x = 273/3

x = 91

x in { -259/3, 91 }

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