abs(4x-3)=1/3

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Solution for abs(4x-3)=1/3 equation:


x in (-oo:+oo)

abs(4*x-3) <= 1/3 // - 1/3

abs(4*x-3)-(1/3) <= 0

abs(4*x-3)-1/3 <= 0

abs(4*x-3)-1/3 <= 0

x in (-oo:+oo)

abs(4*x-3)

4*x-3 >= 0

4*x-3 >= 0 // + 3

4*x >= 3 // : 4

x >= 3/4

x in <3/4:+oo)

4*x-1/3-3 <= 0

x in (-oo:3/4)

3-(4*x)-1/3 <= 0

abs(4*x-3)-1/3 <= 0

/ | 3-(4*x)-1/3 <= 0 i x in (-oo:3/4) | 4*x-1/3-3 <= 0 i x in <3/4:+oo)

x in (-oo:3/4)

3-(4*x)-1/3 <= 0

8/3-4*x <= 0 // - 8/3

-4*x <= -8/3 // : -4

x >= -8/3/(-4)

x >= 2/3

x in <3/4:+oo)

4*x-1/3-3 <= 0

4*x-10/3 <= 0 // + 10/3

4*x <= 10/3 // : 4

x <= 10/3/4

x <= 5/6

x in <2/3:5/6>

<2/3:5/6>

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