abs(8x+1)+5=2

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Solution for abs(8x+1)+5=2 equation:


Simplifying
abs(8x + 1) + 5 = 2

Reorder the terms:
abs(1 + 8x) + 5 = 2
(1 * abs + 8x * abs) + 5 = 2
(1abs + 8absx) + 5 = 2

Reorder the terms:
5 + 1abs + 8absx = 2

Solving
5 + 1abs + 8absx = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 1abs + -5 + 8absx = 2 + -5

Reorder the terms:
5 + -5 + 1abs + 8absx = 2 + -5

Combine like terms: 5 + -5 = 0
0 + 1abs + 8absx = 2 + -5
1abs + 8absx = 2 + -5

Combine like terms: 2 + -5 = -3
1abs + 8absx = -3

Reorder the terms:
3 + 1abs + 8absx = -3 + 3

Combine like terms: -3 + 3 = 0
3 + 1abs + 8absx = 0

The solution to this equation could not be determined.

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