abs(X+2)+abs(2x+1)=5

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Solution for abs(X+2)+abs(2x+1)=5 equation: 


Simplifying
abs(X + 2) + abs(2x + 1) = 5

Reorder the terms:
abs(2 + X) + abs(2x + 1) = 5
(2 * abs + X * abs) + abs(2x + 1) = 5
(2abs + absX) + abs(2x + 1) = 5

Reorder the terms:
2abs + absX + abs(1 + 2x) = 5
2abs + absX + (1 * abs + 2x * abs) = 5
2abs + absX + (1abs + 2absx) = 5

Reorder the terms:
2abs + 1abs + absX + 2absx = 5

Combine like terms: 2abs + 1abs = 3abs
3abs + absX + 2absx = 5

Solving
3abs + absX + 2absx = 5

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-5 + 3abs + absX + 2absx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 3abs + absX + 2absx = 0

The solution to this equation could not be determined.

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