abs(z+-3i)=abs(z)

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Solution for abs(z+-3i)=abs(z) equation:


Simplifying
abs(z + -3i) = abs(z)

Reorder the terms:
abs(-3i + z) = abs(z)
(-3i * abs + z * abs) = abs(z)
(-3abis + absz) = abs(z)

Multiply abs * z
-3abis + absz = absz

Add '-1absz' to each side of the equation.
-3abis + absz + -1absz = absz + -1absz

Combine like terms: absz + -1absz = 0
-3abis + 0 = absz + -1absz
-3abis = absz + -1absz

Combine like terms: absz + -1absz = 0
-3abis = 0

Solving
-3abis = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '-3'.
abis = 0

Simplifying
abis = 0

The solution to this equation could not be determined.

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