abs(z+i)+abs(z-i)=4

Solution for abs(z+i)+abs(z-i)=4 equation:

Simplifying
abs(z + i) + abs(z + -1i) = 4

Reorder the terms:
abs(i + z) + abs(z + -1i) = 4
(i * abs + z * abs) + abs(z + -1i) = 4
(abis + absz) + abs(z + -1i) = 4

Reorder the terms:
abis + absz + abs(-1i + z) = 4
abis + absz + (-1i * abs + z * abs) = 4
abis + absz + (-1abis + absz) = 4

Reorder the terms:
abis + -1abis + absz + absz = 4

Combine like terms: abis + -1abis = 0
0 + absz + absz = 4
absz + absz = 4

Combine like terms: absz + absz = 2absz
2absz = 4

Solving
2absz = 4

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '2bsz'.
a = 2b-1s-1z-1

Simplifying
a = 2b-1s-1z-1