abs(z-i)=z(z-i)

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Solution for abs(z-i)=z(z-i) equation:


Simplifying
abs(z + -1i) = z(z + -1i)

Reorder the terms:
abs(-1i + z) = z(z + -1i)
(-1i * abs + z * abs) = z(z + -1i)
(-1abis + absz) = z(z + -1i)

Reorder the terms:
-1abis + absz = z(-1i + z)
-1abis + absz = (-1i * z + z * z)
-1abis + absz = (-1iz + z2)

Solving
-1abis + absz = -1iz + z2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Reorder the terms:
-1abis + absz + iz + -1z2 = -1iz + iz + z2 + -1z2

Combine like terms: -1iz + iz = 0
-1abis + absz + iz + -1z2 = 0 + z2 + -1z2
-1abis + absz + iz + -1z2 = z2 + -1z2

Combine like terms: z2 + -1z2 = 0
-1abis + absz + iz + -1z2 = 0

The solution to this equation could not be determined.

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