(-0.2)/(x)+(-0.3)/(x) - add fractions

Solution for the given fractions

• -0.2/x + -0.3/x = ?
• The common denominator of the two fractions is: x^2
• -0.2/x = (-0.2*x)/(x*x) = (-0.2*x)/(x^2)
• -0.3/x = (-0.3*x)/(x*x) = (-0.3*x)/(x^2)
• Fractions adjusted to a common denominator
• -0.2/x + -0.3/x = (-0.2*x)/(x^2) + (-0.3*x)/(x^2)
• (-0.2*x)/(x^2) + (-0.3*x)/(x^2) = (-0.2*x-0.3*x)/(x^2)
• (-0.2*x-0.3*x)/(x^2) = (-0.5*x)/(x^2)
• (-0.5*x)/(x^2) = -0.5*x^-1

Solution for the given fractions

$ -\frac{0.2}{x }+ -\frac{0.3}{x }=? $

The common denominator of the two fractions is: x^2

$ -\frac{0.2}{x }= \frac{(-0.2*x)}{(x*x)} = \frac{(-0.2*x)}{(x^2)} $

$ -\frac{0.3}{x }= \frac{(-0.3*x)}{(x*x)} = \frac{(-0.3*x)}{(x^2)} $

Fractions adjusted to a common denominator

$ -\frac{0.2}{x }+ -\frac{0.3}{x }= \frac{(-0.2*x)}{(x^2)} + \frac{(-0.3*x)}{(x^2)} $

$ \frac{(-0.2*x)}{(x^2)} + \frac{(-0.3*x)}{(x^2)} = \frac{(-0.2*x-0.3*x)}{(x^2)} $

$ \frac{(-0.2*x-0.3*x)}{(x^2)} = \frac{(-0.5*x)}{(x^2)} $

$ \frac{(-0.5*x)}{(x^2)} = -0.5*x^-1 $

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