(-2)/(9)+(-19)/(45) - add fractions

Solution for the given fractions

• -2/9 + -19/45 = ?
• The common denominator of the two fractions is: 45
• -2/9 = (-2*5)/(5*9) = -10/45
• -19/45 = (-19*1)/(1*45) = -19/45
• Fractions adjusted to a common denominator
• -2/9 + -19/45 = -10/45 + -19/45
• -10/45 + -19/45 = (-19-10)/45
• (-19-10)/45 = -29/45

Solution for the given fractions

$ -\frac{2}{9 }+ -\frac{19}{45 }=? $

The common denominator of the two fractions is: 45

$ -\frac{2}{9 }= \frac{(-2*5)}{(5*9)} = -\frac{10}{45} $

$ -\frac{19}{45 }= \frac{(-19*1)}{(1*45)} = -\frac{19}{45} $

Fractions adjusted to a common denominator

$ -\frac{2}{9 }+ -\frac{19}{45 }= -\frac{10}{45 }+ -\frac{19}{45} $

$ -\frac{10}{45 }+ -\frac{19}{45 }= \frac{(-19-10)}{45} $

$ \frac{(-19-10)}{45 }= -\frac{29}{45} $

$ $

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