(1)/(4)+(1)/(2*(4/5)) - add fractions

Solution for the given fractions

• 1/4 + 1/(2*(4/5)) = ?
• The common denominator of the two fractions is: 32/5
• 1/4 = (1*2*(4/5))/(2*4*(4/5)) = 8/5/32/5
• 1/(2*(4/5)) = (1*4)/(2*4*(4/5)) = 4/32/5
• Fractions adjusted to a common denominator
• 1/4 + 1/(2*(4/5)) = 8/5/32/5 + 4/32/5
• 8/5/32/5 + 4/32/5 = (8/5+4)/32/5
• (8/5+4)/32/5 = 28/5/32/5
• 28/5/32/5 = 7/8

Solution for the given fractions

$ \frac{1}{4 }+\frac{ 1}{(2*(\frac{4}{5}))} =? $

The common denominator of the two fractions is: 32/5

$ \frac{1}{4 }= \frac{(1*2*(\frac{4}{5}))}{(2*4*(\frac{4}{5}))} =\frac{\frac{\frac{ 8}{5}{32}{5}}} $

$ \frac{1}{(2*(\frac{4}{5}))} = \frac{(1*4)}{(2*4*(\frac{4}{5}))} =\frac{\frac{ 4}{32}{5}} $

Fractions adjusted to a common denominator

$ \frac{1}{4 }+\frac{ 1}{(2*(\frac{4}{5}))} =\frac{\frac{\frac{ 8}{5}{32}{5 }}}+\frac{\frac{ 4}{32}{5}} $

$ \frac{8}{5}{32}{5 }}}+\frac{\frac{ 4}{32}{5 }}= \frac{(\frac{8}{5}+4)\frac{}{32}{5}} $

$ \frac{(\frac{8}{5}+4)\frac{}{32}{5 }}=\frac{\frac{\frac{ 28}{5}{32}{5}}} $

$ \frac{28}{5}{32}{5 }}}=\frac{ 7}{8} $

$ $

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