(17)/(12)+(41/4)/(x) - add fractions

Solution for the given fractions

• 17/12 + (41/4)/x = ?
• The common denominator of the two fractions is: 12*x
• 17/12 = (17*x)/(12*x) = (17*x)/(12*x)
• (41/4)/x = (12*(41/4))/(12*x) = 123/(12*x)
• Fractions adjusted to a common denominator
• 17/12 + (41/4)/x = (17*x)/(12*x) + 123/(12*x)
• (17*x)/(12*x) + 123/(12*x) = (17*x+123)/(12*x)
• (17*x+123)/(12*x) = (17*x+123)/(12*x)

Solution for the given fractions

$ \frac{17}{12 }+ \frac{(\frac{41}{4})}{x }=? $

The common denominator of the two fractions is: 12*x

$ \frac{17}{12 }= \frac{(17*x)}{(12*x)} = \frac{(17*x)}{(12*x)} $

$ \frac{(\frac{41}{4})}{x }= \frac{(12*(\frac{41}{4}))}{(12*x)} =\frac{ 123}{(12*x)} $

Fractions adjusted to a common denominator

$ \frac{17}{12 }+ \frac{(\frac{41}{4})}{x }= \frac{(17*x)}{(12*x)} +\frac{ 123}{(12*x)} $

$ \frac{(17*x)}{(12*x)} +\frac{ 123}{(12*x)} = \frac{(17*x+123)}{(12*x)} $

$ \frac{(17*x+123)}{(12*x)} = \frac{(17*x+123)}{(12*x)} $

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