(2)/(Y-1)+(3)/(Y+3) - add fractions

Solution for the given fractions

• 2/(Y-1) + 3/(Y+3) = ?
• The common denominator of the two fractions is: (Y-1)*(Y+3)
• 2/(Y-1) = (2*(Y+3))/((Y-1)*(Y+3)) = (2*(Y+3))/((Y-1)*(Y+3))
• 3/(Y+3) = (3*(Y-1))/((Y+3)*(Y-1)) = (3*(Y-1))/((Y-1)*(Y+3))
• Fractions adjusted to a common denominator
• 2/(Y-1) + 3/(Y+3) = (2*(Y+3))/((Y-1)*(Y+3)) + (3*(Y-1))/((Y-1)*(Y+3))
• (2*(Y+3))/((Y-1)*(Y+3)) + (3*(Y-1))/((Y-1)*(Y+3)) = (2*(Y+3)+3*(Y-1))/((Y-1)*(Y+3))
• (2*(Y+3)+3*(Y-1))/((Y-1)*(Y+3)) = (2*(Y+3)+3*(Y-1))/((Y-1)*(Y+3))

Solution for the given fractions

$ \frac{2}{(Y-1)} +\frac{ 3}{(Y+3)} =? $

The common denominator of the two fractions is: (Y-1)*(Y+3)

$ \frac{2}{(Y-1)} = \frac{(2*(Y+3))}{((Y-1)*(Y+3))} = \frac{(2*(Y+3))}{((Y-1)*(Y+3))} $

$ \frac{3}{(Y+3)} = \frac{(3*(Y-1))}{((Y+3)*(Y-1))} = \frac{(3*(Y-1))}{((Y-1)*(Y+3))} $

Fractions adjusted to a common denominator

$ \frac{2}{(Y-1)} +\frac{ 3}{(Y+3)} = \frac{(2*(Y+3))}{((Y-1)*(Y+3))} + \frac{(3*(Y-1))}{((Y-1)*(Y+3))} $

$ \frac{(2*(Y+3))}{((Y-1)*(Y+3))} + \frac{(3*(Y-1))}{((Y-1)*(Y+3))} = \frac{(2*(Y+3)+3*(Y-1))}{((Y-1)*(Y+3))} $

$ \frac{(2*(Y+3)+3*(Y-1))}{((Y-1)*(Y+3))} = \frac{(2*(Y+3)+3*(Y-1))}{((Y-1)*(Y+3))} $

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