(2x+13)/(3)+(x-13)/(4) - add fractions

Solution for the given fractions

• (2*x+13)/3 + (x-13)/4 = ?
• The common denominator of the two fractions is: 12
• (2*x+13)/3 = (4*(2*x+13))/(3*4) = (4*(2*x+13))/12
• (x-13)/4 = (3*(x-13))/(3*4) = (3*(x-13))/12
• Fractions adjusted to a common denominator
• (2*x+13)/3 + (x-13)/4 = (4*(2*x+13))/12 + (3*(x-13))/12
• (4*(2*x+13))/12 + (3*(x-13))/12 = (4*(2*x+13)+3*(x-13))/12
• (4*(2*x+13)+3*(x-13))/12 = (4*(2*x+13)+3*(x-13))/12

Solution for the given fractions

$ \frac{(2*x+13)}{3 }+ \frac{(x-13)}{4 }=? $

The common denominator of the two fractions is: 12

$ \frac{(2*x+13)}{3 }= \frac{(4*(2*x+13))}{(3*4)} = \frac{(4*(2*x+13))}{12} $

$ \frac{(x-13)}{4 }= \frac{(3*(x-13))}{(3*4)} = \frac{(3*(x-13))}{12} $

Fractions adjusted to a common denominator

$ \frac{(2*x+13)}{3 }+ \frac{(x-13)}{4 }= \frac{(4*(2*x+13))}{12 }+ \frac{(3*(x-13))}{12} $

$ \frac{(4*(2*x+13))}{12 }+ \frac{(3*(x-13))}{12 }= \frac{(4*(2*x+13)+3*(x-13))}{12} $

$ \frac{(4*(2*x+13)+3*(x-13))}{12 }= \frac{(4*(2*x+13)+3*(x-13))}{12} $

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