(2x-3)/(4)+(x-4-x+1)/(24) - add fractions

Solution for the given fractions

• (2*x-3)/4 + (x-x-4+1)/24 = ?
• The common denominator of the two fractions is: 24
• (2*x-3)/4 = (6*(2*x-3))/(4*6) = (6*(2*x-3))/24
• (x-x-4+1)/24 = (1*(x-x-4+1))/(1*24) = -3/24
• Fractions adjusted to a common denominator
• (2*x-3)/4 + (x-x-4+1)/24 = (6*(2*x-3))/24 + -3/24
• (6*(2*x-3))/24 + -3/24 = (6*(2*x-3)-3)/24
• (6*(2*x-3)-3)/24 = (6*(2*x-3)-3)/24

Solution for the given fractions

$ \frac{(2*x-3)}{4 }+ \frac{(x-x-4+1)}{24 }=? $

The common denominator of the two fractions is: 24

$ \frac{(2*x-3)}{4 }= \frac{(6*(2*x-3))}{(4*6)} = \frac{(6*(2*x-3))}{24} $

$ \frac{(x-x-4+1)}{24 }= \frac{(1*(x-x-4+1))}{(1*24)} = -\frac{3}{24} $

Fractions adjusted to a common denominator

$ \frac{(2*x-3)}{4 }+ \frac{(x-x-4+1)}{24 }= \frac{(6*(2*x-3))}{24 }+ -\frac{3}{24} $

$ \frac{(6*(2*x-3))}{24 }+ -\frac{3}{24 }= \frac{(6*(2*x-3)-3)}{24} $

$ \frac{(6*(2*x-3)-3)}{24 }= \frac{(6*(2*x-3)-3)}{24} $

$ $

see mathematical notation