(3)/(40)+(1)/(3) - add fractions

Solution for the given fractions

• 3/40 + 1/3 = ?
• The common denominator of the two fractions is: 120
• 3/40 = (3*3)/(3*40) = 9/120
• 1/3 = (1*40)/(3*40) = 40/120
• Fractions adjusted to a common denominator
• 3/40 + 1/3 = 9/120 + 40/120
• 9/120 + 40/120 = (9+40)/120
• (9+40)/120 = 49/120

Solution for the given fractions

$ \frac{3}{40 }+\frac{ 1}{3 }=? $

The common denominator of the two fractions is: 120

$ \frac{3}{40 }= \frac{(3*3)}{(3*40)} =\frac{ 9}{120} $

$ \frac{1}{3 }= \frac{(1*40)}{(3*40)} =\frac{ 40}{120} $

Fractions adjusted to a common denominator

$ \frac{3}{40 }+\frac{ 1}{3 }=\frac{ 9}{120 }+\frac{ 40}{120} $

$ \frac{9}{120 }+\frac{ 40}{120 }= \frac{(9+40)}{120} $

$ \frac{(9+40)}{120 }=\frac{ 49}{120} $

$ $

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