(3)/(x-2)+(4)/(x) - add fractions

Solution for the given fractions

• 3/(x-2) + 4/x = ?
• The common denominator of the two fractions is: x*(x-2)
• 3/(x-2) = (3*x)/(x*(x-2)) = (3*x)/(x*(x-2))
• 4/x = (4*(x-2))/(x*(x-2)) = (4*(x-2))/(x*(x-2))
• Fractions adjusted to a common denominator
• 3/(x-2) + 4/x = (3*x)/(x*(x-2)) + (4*(x-2))/(x*(x-2))
• (3*x)/(x*(x-2)) + (4*(x-2))/(x*(x-2)) = (4*(x-2)+3*x)/(x*(x-2))
• (4*(x-2)+3*x)/(x*(x-2)) = (4*(x-2)+3*x)/(x*(x-2))

Solution for the given fractions

$ \frac{3}{(x-2)} +\frac{ 4}{x }=? $

The common denominator of the two fractions is: x*(x-2)

$ \frac{3}{(x-2)} = \frac{(3*x)}{(x*(x-2))} = \frac{(3*x)}{(x*(x-2))} $

$ \frac{4}{x }= \frac{(4*(x-2))}{(x*(x-2))} = \frac{(4*(x-2))}{(x*(x-2))} $

Fractions adjusted to a common denominator

$ \frac{3}{(x-2)} +\frac{ 4}{x }= \frac{(3*x)}{(x*(x-2))} + \frac{(4*(x-2))}{(x*(x-2))} $

$ \frac{(3*x)}{(x*(x-2))} + \frac{(4*(x-2))}{(x*(x-2))} = \frac{(4*(x-2)+3*x)}{(x*(x-2))} $

$ \frac{(4*(x-2)+3*x)}{(x*(x-2))} = \frac{(4*(x-2)+3*x)}{(x*(x-2))} $

$ $

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