(3x)/(x-8)+(24)/(8-x) - add fractions

Solution for the given fractions

• (3*x)/(x-8) + 24/(8-x) = ?
• The common denominator of the two fractions is: (x-8)*(8-x)
• (3*x)/(x-8) = (3*x*(8-x))/((x-8)*(8-x)) = (3*x*(8-x))/((x-8)*(8-x))
• 24/(8-x) = (24*(x-8))/((8-x)*(x-8)) = (24*(x-8))/((x-8)*(8-x))
• Fractions adjusted to a common denominator
• (3*x)/(x-8) + 24/(8-x) = (3*x*(8-x))/((x-8)*(8-x)) + (24*(x-8))/((x-8)*(8-x))
• (3*x*(8-x))/((x-8)*(8-x)) + (24*(x-8))/((x-8)*(8-x)) = (3*x*(8-x)+24*(x-8))/((x-8)*(8-x))
• (3*x*(8-x)+24*(x-8))/((x-8)*(8-x)) = (3*x*(8-x)+24*(x-8))/((x-8)*(8-x))

Solution for the given fractions

$ \frac{(3*x)}{(x-8)} +\frac{ 24}{(8-x)} =? $

The common denominator of the two fractions is: (x-8)*(8-x)

$ \frac{(3*x)}{(x-8)} = \frac{(3*x*(8-x))}{((x-8)*(8-x))} = \frac{(3*x*(8-x))}{((x-8)*(8-x))} $

$ \frac{24}{(8-x)} = \frac{(24*(x-8))}{((8-x)*(x-8))} = \frac{(24*(x-8))}{((x-8)*(8-x))} $

Fractions adjusted to a common denominator

$ \frac{(3*x)}{(x-8)} +\frac{ 24}{(8-x)} = \frac{(3*x*(8-x))}{((x-8)*(8-x))} + \frac{(24*(x-8))}{((x-8)*(8-x))} $

$ \frac{(3*x*(8-x))}{((x-8)*(8-x))} + \frac{(24*(x-8))}{((x-8)*(8-x))} = \frac{(3*x*(8-x)+24*(x-8))}{((x-8)*(8-x))} $

$ \frac{(3*x*(8-x)+24*(x-8))}{((x-8)*(8-x))} = \frac{(3*x*(8-x)+24*(x-8))}{((x-8)*(8-x))} $

$ $

see mathematical notation