(3x+14)/(5)+(x+54)/(7) - add fractions

Solution for the given fractions

• (3*x+14)/5 + (x+54)/7 = ?
• The common denominator of the two fractions is: 35
• (3*x+14)/5 = (7*(3*x+14))/(5*7) = (7*(3*x+14))/35
• (x+54)/7 = (5*(x+54))/(5*7) = (5*(x+54))/35
• Fractions adjusted to a common denominator
• (3*x+14)/5 + (x+54)/7 = (7*(3*x+14))/35 + (5*(x+54))/35
• (7*(3*x+14))/35 + (5*(x+54))/35 = (7*(3*x+14)+5*(x+54))/35
• (7*(3*x+14)+5*(x+54))/35 = (7*(3*x+14)+5*(x+54))/35

Solution for the given fractions

$ \frac{(3*x+14)}{5 }+ \frac{(x+54)}{7 }=? $

The common denominator of the two fractions is: 35

$ \frac{(3*x+14)}{5 }= \frac{(7*(3*x+14))}{(5*7)} = \frac{(7*(3*x+14))}{35} $

$ \frac{(x+54)}{7 }= \frac{(5*(x+54))}{(5*7)} = \frac{(5*(x+54))}{35} $

Fractions adjusted to a common denominator

$ \frac{(3*x+14)}{5 }+ \frac{(x+54)}{7 }= \frac{(7*(3*x+14))}{35 }+ \frac{(5*(x+54))}{35} $

$ \frac{(7*(3*x+14))}{35 }+ \frac{(5*(x+54))}{35 }= \frac{(7*(3*x+14)+5*(x+54))}{35} $

$ \frac{(7*(3*x+14)+5*(x+54))}{35 }= \frac{(7*(3*x+14)+5*(x+54))}{35} $

$ $

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