(9)/(8x)+(3)/(8x) - add fractions

Solution for the given fractions

• 9/(8*x) + 3/(8*x) = ?
• The common denominator of the two fractions is: 64*x^2
• 9/(8*x) = (8*9*x)/(8*8*x*x) = (72*x)/(64*x^2)
• 3/(8*x) = (3*8*x)/(8*8*x*x) = (24*x)/(64*x^2)
• Fractions adjusted to a common denominator
• 9/(8*x) + 3/(8*x) = (72*x)/(64*x^2) + (24*x)/(64*x^2)
• (72*x)/(64*x^2) + (24*x)/(64*x^2) = (72*x+24*x)/(64*x^2)
• (72*x+24*x)/(64*x^2) = (96*x)/(64*x^2)
• (96*x)/(64*x^2) = (3*x^-1)/2

Solution for the given fractions

$ \frac{9}{(8*x)} +\frac{ 3}{(8*x)} =? $

The common denominator of the two fractions is: 64*x^2

$ \frac{9}{(8*x)} = \frac{(8*9*x)}{(8*8*x*x)} = \frac{(72*x)}{(64*x^2)} $

$ \frac{3}{(8*x)} = \frac{(3*8*x)}{(8*8*x*x)} = \frac{(24*x)}{(64*x^2)} $

Fractions adjusted to a common denominator

$ \frac{9}{(8*x)} +\frac{ 3}{(8*x)} = \frac{(72*x)}{(64*x^2)} + \frac{(24*x)}{(64*x^2)} $

$ \frac{(72*x)}{(64*x^2)} + \frac{(24*x)}{(64*x^2)} = \frac{(72*x+24*x)}{(64*x^2)} $

$ \frac{(72*x+24*x)}{(64*x^2)} = \frac{(96*x)}{(64*x^2)} $

$ \frac{(96*x)}{(64*x^2)} = \frac{(3*x^-1)}{2} $

$ $

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