(X)/(4)+(3x)/(8) - add fractions

Solution for the given fractions

• X/4 + (3*x)/8 = ?
• The common denominator of the two fractions is: 8
• X/4 = (2*X)/(2*4) = (2*X)/8
• (3*x)/8 = (1*3*x)/(1*8) = (3*x)/8
• Fractions adjusted to a common denominator
• X/4 + (3*x)/8 = (2*X)/8 + (3*x)/8
• (2*X)/8 + (3*x)/8 = (2*X+3*x)/8
• (2*X+3*x)/8 = (2*X+3*x)/8

Solution for the given fractions

$ \frac{X}{4 }+ \frac{(3*x)}{8 }=? $

The common denominator of the two fractions is: 8

$ \frac{X}{4 }= \frac{(2*X)}{(2*4)} = \frac{(2*X)}{8} $

$ \frac{(3*x)}{8 }= \frac{(1*3*x)}{(1*8)} = \frac{(3*x)}{8} $

Fractions adjusted to a common denominator

$ \frac{X}{4 }+ \frac{(3*x)}{8 }= \frac{(2*X)}{8 }+ \frac{(3*x)}{8} $

$ \frac{(2*X)}{8 }+ \frac{(3*x)}{8 }= \frac{(2*X+3*x)}{8} $

$ \frac{(2*X+3*x)}{8 }= \frac{(2*X+3*x)}{8} $

$ $

see mathematical notation