(m-23)/(6)+(6m-14)/(7) - add fractions

Solution for the given fractions

• (m-23)/6 + (6*m-14)/7 = ?
• The common denominator of the two fractions is: 42
• (m-23)/6 = (7*(m-23))/(6*7) = (7*(m-23))/42
• (6*m-14)/7 = (6*(6*m-14))/(6*7) = (6*(6*m-14))/42
• Fractions adjusted to a common denominator
• (m-23)/6 + (6*m-14)/7 = (7*(m-23))/42 + (6*(6*m-14))/42
• (7*(m-23))/42 + (6*(6*m-14))/42 = (7*(m-23)+6*(6*m-14))/42
• (7*(m-23)+6*(6*m-14))/42 = (7*(m-23)+6*(6*m-14))/42

Solution for the given fractions

$ \frac{(m-23)}{6 }+ \frac{(6*m-14)}{7 }=? $

The common denominator of the two fractions is: 42

$ \frac{(m-23)}{6 }= \frac{(7*(m-23))}{(6*7)} = \frac{(7*(m-23))}{42} $

$ \frac{(6*m-14)}{7 }= \frac{(6*(6*m-14))}{(6*7)} = \frac{(6*(6*m-14))}{42} $

Fractions adjusted to a common denominator

$ \frac{(m-23)}{6 }+ \frac{(6*m-14)}{7 }= \frac{(7*(m-23))}{42 }+ \frac{(6*(6*m-14))}{42} $

$ \frac{(7*(m-23))}{42 }+ \frac{(6*(6*m-14))}{42 }= \frac{(7*(m-23)+6*(6*m-14))}{42} $

$ \frac{(7*(m-23)+6*(6*m-14))}{42 }= \frac{(7*(m-23)+6*(6*m-14))}{42} $

$ $

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