(x+4)/(9)+(x+21)/(2) - add fractions

Solution for the given fractions

• (x+4)/9 + (x+21)/2 = ?
• The common denominator of the two fractions is: 18
• (x+4)/9 = (2*(x+4))/(2*9) = (2*(x+4))/18
• (x+21)/2 = (9*(x+21))/(2*9) = (9*(x+21))/18
• Fractions adjusted to a common denominator
• (x+4)/9 + (x+21)/2 = (2*(x+4))/18 + (9*(x+21))/18
• (2*(x+4))/18 + (9*(x+21))/18 = (2*(x+4)+9*(x+21))/18
• (2*(x+4)+9*(x+21))/18 = (2*(x+4)+9*(x+21))/18

Solution for the given fractions

$ \frac{(x+4)}{9 }+ \frac{(x+21)}{2 }=? $

The common denominator of the two fractions is: 18

$ \frac{(x+4)}{9 }= \frac{(2*(x+4))}{(2*9)} = \frac{(2*(x+4))}{18} $

$ \frac{(x+21)}{2 }= \frac{(9*(x+21))}{(2*9)} = \frac{(9*(x+21))}{18} $

Fractions adjusted to a common denominator

$ \frac{(x+4)}{9 }+ \frac{(x+21)}{2 }= \frac{(2*(x+4))}{18 }+ \frac{(9*(x+21))}{18} $

$ \frac{(2*(x+4))}{18 }+ \frac{(9*(x+21))}{18 }= \frac{(2*(x+4)+9*(x+21))}{18} $

$ \frac{(2*(x+4)+9*(x+21))}{18 }= \frac{(2*(x+4)+9*(x+21))}{18} $

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