(1)/(2u)+(5)/(6v) - adding of fractions

Solution for the given fractions

• 1/(2*u) + 5/(6*v) = ?
• The common denominator of the two fractions is: 12*u*v
• 1/(2*u) = (1*6*v)/(2*6*u*v) = (6*v)/(12*u*v)
• 5/(6*v) = (2*5*u)/(2*6*u*v) = (10*u)/(12*u*v)
• Fractions adjusted to a common denominator
• 1/(2*u) + 5/(6*v) = (6*v)/(12*u*v) + (10*u)/(12*u*v)
• (6*v)/(12*u*v) + (10*u)/(12*u*v) = (10*u+6*v)/(12*u*v)
• (10*u+6*v)/(12*u*v) = (10*u+6*v)/(12*u*v)

Solution for the given fractions

$ \frac{1}{(2*u)} +\frac{ 5}{(6*v)} =? $

The common denominator of the two fractions is: 12*u*v

$ \frac{1}{(2*u)} = \frac{(1*6*v)}{(2*6*u*v)} = \frac{(6*v)}{(12*u*v)} $

$ \frac{5}{(6*v)} = \frac{(2*5*u)}{(2*6*u*v)} = \frac{(10*u)}{(12*u*v)} $

Fractions adjusted to a common denominator

$ \frac{1}{(2*u)} +\frac{ 5}{(6*v)} = \frac{(6*v)}{(12*u*v)} + \frac{(10*u)}{(12*u*v)} $

$ \frac{(6*v)}{(12*u*v)} + \frac{(10*u)}{(12*u*v)} = \frac{(10*u+6*v)}{(12*u*v)} $

$ \frac{(10*u+6*v)}{(12*u*v)} = \frac{(10*u+6*v)}{(12*u*v)} $

$ $

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