(1)/(A2b)+(3)/(A4) - adding of fractions

Solution for the given fractions

• 1/(A^2*b) + 3/(A^4) = ?
• The common denominator of the two fractions is: A^6*b
• 1/(A^2*b) = (1*A^4)/(A^2*A^4*b) = (A^4)/(A^6*b)
• 3/(A^4) = (3*A^2*b)/(A^2*A^4*b) = (3*A^2*b)/(A^6*b)
• Fractions adjusted to a common denominator
• 1/(A^2*b) + 3/(A^4) = (A^4)/(A^6*b) + (3*A^2*b)/(A^6*b)
• (A^4)/(A^6*b) + (3*A^2*b)/(A^6*b) = (A^4+3*A^2*b)/(A^6*b)
• (A^4+3*A^2*b)/(A^6*b) = (A^4+3*A^2*b)/(A^6*b)

Solution for the given fractions

$ \frac{1}{(A^2*b)} +\frac{ 3}{(A^4)} =? $

The common denominator of the two fractions is: A^6*b

$ \frac{1}{(A^2*b)} = \frac{(1*A^4)}{(A^2*A^4*b)} = \frac{(A^4)}{(A^6*b)} $

$ \frac{3}{(A^4)} = \frac{(3*A^2*b)}{(A^2*A^4*b)} = \frac{(3*A^2*b)}{(A^6*b)} $

Fractions adjusted to a common denominator

$ \frac{1}{(A^2*b)} +\frac{ 3}{(A^4)} = \frac{(A^4)}{(A^6*b)} + \frac{(3*A^2*b)}{(A^6*b)} $

$ \frac{(A^4)}{(A^6*b)} + \frac{(3*A^2*b)}{(A^6*b)} = \frac{(A^4+3*A^2*b)}{(A^6*b)} $

$ \frac{(A^4+3*A^2*b)}{(A^6*b)} = \frac{(A^4+3*A^2*b)}{(A^6*b)} $

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