(25+6)/(42+7)+(7)/(21) - adding of fractions

Solution for the given fractions

• (6+25)/(7+42) + 7/21 = ?
• The common denominator of the two fractions is: 1029
• (6+25)/(7+42) = (21*(6+25))/(21*(7+42)) = 651/1029
• 7/21 = (7*(7+42))/(21*(7+42)) = 343/1029
• Fractions adjusted to a common denominator
• (6+25)/(7+42) + 7/21 = 651/1029 + 343/1029
• 651/1029 + 343/1029 = (343+651)/1029
• (343+651)/1029 = 994/1029
• 994/1029 = 142/147

Solution for the given fractions

$ \frac{(6+25)}{(7+42)} +\frac{ 7}{21 }=? $

The common denominator of the two fractions is: 1029

$ \frac{(6+25)}{(7+42)} = \frac{(21*(6+25))}{(21*(7+42))} =\frac{ 651}{1029} $

$ \frac{7}{21 }= \frac{(7*(7+42))}{(21*(7+42))} =\frac{ 343}{1029} $

Fractions adjusted to a common denominator

$ \frac{(6+25)}{(7+42)} +\frac{ 7}{21 }=\frac{ 651}{1029 }+\frac{ 343}{1029} $

$ \frac{651}{1029 }+\frac{ 343}{1029 }= \frac{(343+651)}{1029} $

$ \frac{(343+651)}{1029 }=\frac{ 994}{1029} $

$ \frac{994}{1029 }=\frac{ 142}{147} $

$ $

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