(32)/(48)+(n)/(10) - adding of fractions

Solution for the given fractions

• 32/48 + n/10 = ?
• The common denominator of the two fractions is: 240
• 32/48 = (5*32)/(5*48) = 160/240
• n/10 = (24*n)/(10*24) = (24*n)/240
• Fractions adjusted to a common denominator
• 32/48 + n/10 = 160/240 + (24*n)/240
• 160/240 + (24*n)/240 = (24*n+160)/240
• (24*n+160)/240 = (24*n+160)/240

Solution for the given fractions

$ \frac{32}{48 }+\frac{ n}{10 }=? $

The common denominator of the two fractions is: 240

$ \frac{32}{48 }= \frac{(5*32)}{(5*48)} =\frac{ 160}{240} $

$ \frac{n}{10 }= \frac{(24*n)}{(10*24)} = \frac{(24*n)}{240} $

Fractions adjusted to a common denominator

$ \frac{32}{48 }+\frac{ n}{10 }=\frac{ 160}{240 }+ \frac{(24*n)}{240} $

$ \frac{160}{240 }+ \frac{(24*n)}{240 }= \frac{(24*n+160)}{240} $

$ \frac{(24*n+160)}{240 }= \frac{(24*n+160)}{240} $

$ $

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