(3m-5n)/(12m)+(m-6)/(12m) - adding of fractions

(3m-5n)/(12m)+(m-6)/(12m) - step by step solution for the given fractions. Adding of fractions, full explanation.

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    Solution for the given fractions

    • (3*m-(5*n))/(12*m) + (m-6)/(12*m) = ?
    • The common denominator of the two fractions is: 144*m^2
    • (3*m-(5*n))/(12*m) = (12*m*(3*m-(5*n)))/(12*12*m*m) = (12*m*(3*m-5*n))/(144*m^2)
    • (m-6)/(12*m) = (12*m*(m-6))/(12*12*m*m) = (12*m*(m-6))/(144*m^2)
    • Fractions adjusted to a common denominator
    • (3*m-(5*n))/(12*m) + (m-6)/(12*m) = (12*m*(3*m-5*n))/(144*m^2) + (12*m*(m-6))/(144*m^2)
    • (12*m*(3*m-5*n))/(144*m^2) + (12*m*(m-6))/(144*m^2) = (12*m*(3*m-5*n)+12*m*(m-6))/(144*m^2)
    • (12*m*(3*m-5*n)+12*m*(m-6))/(144*m^2) = (12*m*(3*m-5*n)+12*m*(m-6))/(144*m^2)

    Solution for the given fractions

    $ \frac{(3*m-(5*n))}{(12*m)} + \frac{(m-6)}{(12*m)} =? $

    The common denominator of the two fractions is: 144*m^2

    $ \frac{(3*m-(5*n))}{(12*m)} = \frac{(12*m*(3*m-(5*n)))}{(12*12*m*m)} = \frac{(12*m*(3*m-5*n))}{(144*m^2)} $

    $ \frac{(m-6)}{(12*m)} = \frac{(12*m*(m-6))}{(12*12*m*m)} = \frac{(12*m*(m-6))}{(144*m^2)} $

    Fractions adjusted to a common denominator

    $ \frac{(3*m-(5*n))}{(12*m)} + \frac{(m-6)}{(12*m)} = \frac{(12*m*(3*m-5*n))}{(144*m^2)} + \frac{(12*m*(m-6))}{(144*m^2)} $

    $ \frac{(12*m*(3*m-5*n))}{(144*m^2)} + \frac{(12*m*(m-6))}{(144*m^2)} = \frac{(12*m*(3*m-5*n)+12*m*(m-6))}{(144*m^2)} $

    $ \frac{(12*m*(3*m-5*n)+12*m*(m-6))}{(144*m^2)} = \frac{(12*m*(3*m-5*n)+12*m*(m-6))}{(144*m^2)} $

    $ $

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