(6)/(y)+(2)/(y) - adding of fractions

Solution for the given fractions

• 6/y + 2/y = ?
• The common denominator of the two fractions is: y^2
• 6/y = (6*y)/(y*y) = (6*y)/(y^2)
• 2/y = (2*y)/(y*y) = (2*y)/(y^2)
• Fractions adjusted to a common denominator
• 6/y + 2/y = (6*y)/(y^2) + (2*y)/(y^2)
• (6*y)/(y^2) + (2*y)/(y^2) = (6*y+2*y)/(y^2)
• (6*y+2*y)/(y^2) = (8*y)/(y^2)
• (8*y)/(y^2) = 8*y^-1

Solution for the given fractions

$ \frac{6}{y }+\frac{ 2}{y }=? $

The common denominator of the two fractions is: y^2

$ \frac{6}{y }= \frac{(6*y)}{(y*y)} = \frac{(6*y)}{(y^2)} $

$ \frac{2}{y }= \frac{(2*y)}{(y*y)} = \frac{(2*y)}{(y^2)} $

Fractions adjusted to a common denominator

$ \frac{6}{y }+\frac{ 2}{y }= \frac{(6*y)}{(y^2)} + \frac{(2*y)}{(y^2)} $

$ \frac{(6*y)}{(y^2)} + \frac{(2*y)}{(y^2)} = \frac{(6*y+2*y)}{(y^2)} $

$ \frac{(6*y+2*y)}{(y^2)} = \frac{(8*y)}{(y^2)} $

$ \frac{(8*y)}{(y^2)} = 8*y^-1 $

$ $

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