(7)/(5/8)+(1)/(1/4) - adding of fractions

Solution for the given fractions

• 7/(5/8) + 1/(1/4) = ?
• The common denominator of the two fractions is: 5/32
• 7/(5/8) = (7*(1/4))/((5/8)*(1/4)) = 7/4/5/32
• 1/(1/4) = (1*(5/8))/((1/4)*(5/8)) = 5/8/5/32
• Fractions adjusted to a common denominator
• 7/(5/8) + 1/(1/4) = 7/4/5/32 + 5/8/5/32
• 7/4/5/32 + 5/8/5/32 = (5/8+7/4)/5/32
• (5/8+7/4)/5/32 = 19/8/5/32
• 19/8/5/32 = 76/5

Solution for the given fractions

$ \frac{7}{(\frac{5}{8})} +\frac{ 1}{(\frac{1}{4})} =? $

The common denominator of the two fractions is: 5/32

$ \frac{7}{(\frac{5}{8})} = \frac{(7*(\frac{1}{4}))}{((\frac{5}{8})*(\frac{1}{4}))} =\frac{\frac{\frac{ 7}{4}{5}{32}}} $

$ \frac{1}{(\frac{1}{4})} = \frac{(1*(\frac{5}{8}))}{((\frac{1}{4})*(\frac{5}{8}))} =\frac{\frac{\frac{ 5}{8}{5}{32}}} $

Fractions adjusted to a common denominator

$ \frac{7}{(\frac{5}{8})} +\frac{ 1}{(\frac{1}{4})} =\frac{\frac{\frac{ 7}{4}{5}{32 }}}+\frac{\frac{\frac{ 5}{8}{5}{32}}} $

$ \frac{7}{4}{5}{32 }}}+\frac{\frac{\frac{ 5}{8}{5}{32 }}}= \frac{(\frac{5}{8}+\frac{7}{4})\frac{}{5}{32}} $

$ \frac{(\frac{5}{8}+\frac{7}{4})\frac{}{5}{32 }}=\frac{\frac{\frac{ 19}{8}{5}{32}}} $

$ \frac{19}{8}{5}{32 }}}=\frac{ 76}{5} $

$ $

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