(9v+7)/(7)+(v-4)/(2) - adding of fractions

Solution for the given fractions

• (9*v+7)/7 + (v-4)/2 = ?
• The common denominator of the two fractions is: 14
• (9*v+7)/7 = (2*(9*v+7))/(2*7) = (2*(9*v+7))/14
• (v-4)/2 = (7*(v-4))/(2*7) = (7*(v-4))/14
• Fractions adjusted to a common denominator
• (9*v+7)/7 + (v-4)/2 = (2*(9*v+7))/14 + (7*(v-4))/14
• (2*(9*v+7))/14 + (7*(v-4))/14 = (2*(9*v+7)+7*(v-4))/14
• (2*(9*v+7)+7*(v-4))/14 = (2*(9*v+7)+7*(v-4))/14

Solution for the given fractions

$ \frac{(9*v+7)}{7 }+ \frac{(v-4)}{2 }=? $

The common denominator of the two fractions is: 14

$ \frac{(9*v+7)}{7 }= \frac{(2*(9*v+7))}{(2*7)} = \frac{(2*(9*v+7))}{14} $

$ \frac{(v-4)}{2 }= \frac{(7*(v-4))}{(2*7)} = \frac{(7*(v-4))}{14} $

Fractions adjusted to a common denominator

$ \frac{(9*v+7)}{7 }+ \frac{(v-4)}{2 }= \frac{(2*(9*v+7))}{14 }+ \frac{(7*(v-4))}{14} $

$ \frac{(2*(9*v+7))}{14 }+ \frac{(7*(v-4))}{14 }= \frac{(2*(9*v+7)+7*(v-4))}{14} $

$ \frac{(2*(9*v+7)+7*(v-4))}{14 }= \frac{(2*(9*v+7)+7*(v-4))}{14} $

$ $

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