(2x-12)/(2)+(11m)/(7) - addition of fractions

Solution for the given fractions

• (2*x-12)/2 + (11*m)/7 = ?
• The common denominator of the two fractions is: 14
• (2*x-12)/2 = (7*(2*x-12))/(2*7) = (7*(2*x-12))/14
• (11*m)/7 = (2*11*m)/(2*7) = (22*m)/14
• Fractions adjusted to a common denominator
• (2*x-12)/2 + (11*m)/7 = (7*(2*x-12))/14 + (22*m)/14
• (7*(2*x-12))/14 + (22*m)/14 = (7*(2*x-12)+22*m)/14
• (7*(2*x-12)+22*m)/14 = (7*(2*x-12)+22*m)/14

Solution for the given fractions

$ \frac{(2*x-12)}{2 }+ \frac{(11*m)}{7 }=? $

The common denominator of the two fractions is: 14

$ \frac{(2*x-12)}{2 }= \frac{(7*(2*x-12))}{(2*7)} = \frac{(7*(2*x-12))}{14} $

$ \frac{(11*m)}{7 }= \frac{(2*11*m)}{(2*7)} = \frac{(22*m)}{14} $

Fractions adjusted to a common denominator

$ \frac{(2*x-12)}{2 }+ \frac{(11*m)}{7 }= \frac{(7*(2*x-12))}{14 }+ \frac{(22*m)}{14} $

$ \frac{(7*(2*x-12))}{14 }+ \frac{(22*m)}{14 }= \frac{(7*(2*x-12)+22*m)}{14} $

$ \frac{(7*(2*x-12)+22*m)}{14 }= \frac{(7*(2*x-12)+22*m)}{14} $

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