(3)/(48)+(10)/(1) - addition of fractions

Solution for the given fractions

• 3/48 + 10/1 = ?
• The common denominator of the two fractions is: 48
• 3/48 = (1*3)/(1*48) = 3/48
• 10/1 = (10*48)/(1*48) = 480/48
• Fractions adjusted to a common denominator
• 3/48 + 10/1 = 3/48 + 480/48
• (3+480)/48 = 483/48
• 483/48 = 161/16

Solution for the given fractions

$ \frac{3}{48 }+\frac{ 10}{1 }=? $

The common denominator of the two fractions is: 48

$ \frac{3}{48 }= \frac{(1*3)}{(1*48)} =\frac{ 3}{48} $

$ \frac{10}{1 }= \frac{(10*48)}{(1*48)} =\frac{ 480}{48} $

Fractions adjusted to a common denominator

$ \frac{3}{48 }+\frac{ 10}{1 }=\frac{ 3}{48 }+\frac{ 480}{48} $

$ \frac{(3+480)}{48 }=\frac{ 483}{48} $

$ \frac{483}{48 }=\frac{ 161}{16} $

$ $

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