(7)/(8)+(32)/(1) - addition of fractions

Solution for the given fractions

• 7/8 + 32/1 = ?
• The common denominator of the two fractions is: 8
• 7/8 = (1*7)/(1*8) = 7/8
• 32/1 = (8*32)/(1*8) = 256/8
• Fractions adjusted to a common denominator
• 7/8 + 32/1 = 7/8 + 256/8
• (7+256)/8 = 263/8

Solution for the given fractions

$ \frac{7}{8 }+\frac{ 32}{1 }=? $

The common denominator of the two fractions is: 8

$ \frac{7}{8 }= \frac{(1*7)}{(1*8)} =\frac{ 7}{8} $

$ \frac{32}{1 }= \frac{(8*32)}{(1*8)} =\frac{ 256}{8} $

Fractions adjusted to a common denominator

$ \frac{7}{8 }+\frac{ 32}{1 }=\frac{ 7}{8 }+\frac{ 256}{8} $

$ \frac{(7+256)}{8 }=\frac{ 263}{8} $

$ $

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