(a-1)/(5)+(a+1)/(2) - addition of fractions

Solution for the given fractions

• (a-1)/5 + (a+1)/2 = ?
• The common denominator of the two fractions is: 10
• (a-1)/5 = (2*(a-1))/(2*5) = (2*(a-1))/10
• (a+1)/2 = (5*(a+1))/(2*5) = (5*(a+1))/10
• Fractions adjusted to a common denominator
• (a-1)/5 + (a+1)/2 = (2*(a-1))/10 + (5*(a+1))/10
• (2*(a-1))/10 + (5*(a+1))/10 = (2*(a-1)+5*(a+1))/10
• (2*(a-1)+5*(a+1))/10 = (2*(a-1)+5*(a+1))/10

Solution for the given fractions

$ \frac{(a-1)}{5 }+ \frac{(a+1)}{2 }=? $

The common denominator of the two fractions is: 10

$ \frac{(a-1)}{5 }= \frac{(2*(a-1))}{(2*5)} = \frac{(2*(a-1))}{10} $

$ \frac{(a+1)}{2 }= \frac{(5*(a+1))}{(2*5)} = \frac{(5*(a+1))}{10} $

Fractions adjusted to a common denominator

$ \frac{(a-1)}{5 }+ \frac{(a+1)}{2 }= \frac{(2*(a-1))}{10 }+ \frac{(5*(a+1))}{10} $

$ \frac{(2*(a-1))}{10 }+ \frac{(5*(a+1))}{10 }= \frac{(2*(a-1)+5*(a+1))}{10} $

$ \frac{(2*(a-1)+5*(a+1))}{10 }= \frac{(2*(a-1)+5*(a+1))}{10} $

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